sql - 如何在oracle sql中获取前6个月的数据,从当前月份开始按月分组?
这是我的表:(DATE是在TIMESTAMP数据类型中......这里我提到的是DATE)
DATE(DD/MM/YYYY) VALUE
10/05/2020 3
20/05/2020 7
08/04/2020 12
10/04/2020 28
15/03/2020 13
08/02/2020 12
10/01/2020 28
15/12/2019 13
21/12/2019 18
12/11/2019 17
我想得到
MONTH TOTAL
05/2020 10
04/2020 40
03/2020 13
02/2020 12
01/2020 28
12/2019 31
我应该只到12月,即从今天开始的6个月......先谢谢你!!!
【回答】:
一点点的 WHERE
和 GROUP BY
:
SQL> with test (datum, value) as
2 -- sample data
3 (select timestamp '2020-05-10 00:00:00.000', 3 from dual union all
4 select timestamp '2020-05-20 00:00:00.000', 7 from dual union all
5 select timestamp '2020-04-08 00:00:00.000', 12 from dual union all
6 select timestamp '2020-04-10 00:00:00.000', 28 from dual union all
7 select timestamp '2020-03-15 00:00:00.000', 13 from dual union all
8 select timestamp '2020-02-08 00:00:00.000', 12 from dual union all
9 select timestamp '2020-01-10 00:00:00.000', 28 from dual union all
10 select timestamp '2019-12-15 00:00:00.000', 13 from dual union all
11 select timestamp '2019-12-21 00:00:00.000', 18 from dual union all
12 select timestamp '2019-11-12 00:00:00.000', 17 from dual
13 )
14 -- query you need
15 select to_char(datum, 'yyyy/mm') month,
16 sum(value) total
17 from test
18 where datum >= add_months(trunc(sysdate), -6)
19 group by to_char(datum, 'yyyy/mm')
20 order by month desc;
MONTH TOTAL
------- ----------
2020/05 10
2020/04 40
2020/03 13
2020/02 12
2020/01 28
2019/12 31
6 rows selected.
SQL>
【回答】:嘗試以下方法
select
to_char(date, 'MM-YYYY') as months,
sum(value) as total
from myTable
where date > SYSDATE - INTERVAL '6' MONTH
group by
to_char(date, 'MM-YYYY')